Nordic Mathematical Contest 2005

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Nordic Mathematical Contest 2005



problem 1 Find all positive integers such that the product of the digits of , in decimal notation, equals



The product of the digits of is an integer so digits is even; then

. Now since is odd, so is odd.

is at most

(trivial to show) so

. On the other hand, it is a non-negative

number so

because it is odd, that is,

. Now we just have to check . Inspection shows both work.

, and the product of the

is

the rightmost digit is even, so

Also the product of the digits of

problem 2 Let be positive real numbers. Prove that



By Cauchy Schwartz

By Chebyshev and then Nesbitt,



Indeed very easy! I killed this in 10 seconds.

Q.E.D.

Problem3 There are young people sitting around a large circular table. Of these, at most

has a strong position, if, counting from

in either direction,

are boys. We say that a girl

the number of girls is always strictly larger than the number of boys ( is herself included in the count). Prove that there is always a girl in a strong position.

It's clear that if the result is true for

boys, then it is true for any smaller number

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of boys (just switch some girls into boys till you have

girls and boys.



boys, then the result is

true and by switching back the boys into girls it stays true). We'll prove the result for

This can be done by induction. Suppose the result is true for take

girls and boys. Take any girl

clear there is one), and then go round the table till you find another have something like

the boys in that interval. Among the

.

. Now take away

girls and

. Now , so you'll

which has a boy for a neighbor (it's

where is any of

boys left there's a girl in

a strong position by hypothesis; it's easy to see she's still strong when we put back

Problem4 The circle is inside the circle , and the circles touch each other at . A line

through intersects also at , and also at . The tangent to at intersects at and . The tangents of passing thorugh touch at and . Prove that , , and are concyclic.

Consider the homotety of center to the tangent of and from here

at

which tranforms

. Hence

to

then and

and we are done.

will transform

parallel to



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