山东师范大学10-11电子C语言期末试题
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日 - -- - --月--- - -- - 年---- -- -- - -- - -- - -- - ：---间---时--试---考--- - -- - --- -- - -- - --- -- - 线- - - --业- 专--- -- -- - -- - -- - -- - 封 --）-部---（---院--- -- - -- - -- 密 - --- --名-姓--- --- -- - -- - --- -- - -- - --- -- - -- - -- - -- - 号----学-山东师范大学2010-2011学年第1学期期末考试试题 （时间：120分钟 共100分） 课程编号：080920201、080940201 课程名称：C语言程序设计 试题类别： A考试类型：闭卷 适用年级：2010 适用专业：电子信息工程、电子科学与技术 题号 I II III 总分 阅卷人 复核人 得分 Part Ⅰ For each of the following questions, fill-in one of either: A, B, C, or D on the blanks. （There are 15 questions, each of which is worth 2 mark.total 40.） 得 分 评阅人 1. ( ) 2. ( ) 3. ( ) 4. ( ) 5. ( ) 6. ( ) 7. ( ) 8. ( ) 9. ( ) 10. ( ) 11. ( ) 12. ( ) 13. ( ) 14. ( ) 15. ( ) 16. ( ) 17. ( ) 18. ( ) 19. ( ) 20. ( ) 1. If x is a float variable, the value of expression (x=10/4) is _____ 。 A) 2.5 B) 2.0 C) 3 D) 2 2. If variables are defined and assigned correctly, the expression ______ is wrong. A) a&b B) a^b C) &&x D) a, b 3. According to the declaration: int a[10], *p=a; the expression ______ is wrong. A) a[9] B) p[5] C) *p++ D) a++ 4. ______ is wrong. A) char str[10]; str="string"; B) char str[ ]="string"; C) char *p="string"; D) char *p; p="string"; 5. The precedence of operator _____ is the highest one. A) += B) [] C) & D) ++ 6. The valid C expression of mathematical expression 1≤x≤5 is . A) 1<=x<=5 B) (x> =1)&(x<=5 ) C) (x>=1 )&&(x<=5) D) (1 < =x)||(5> =x) 7. Which one of following marks can be defined as identifier? A) int B)float C) char D)string 8．Having declaration statement: int a=1, b=2, c=3; the value of expression (a>b>c,a
A) 0 B)1 C) 2 D) 3
9. Given the following declarations of arrays, which one is valid.
A) char str[30]= {12,23,34}; B) int a[ ] ; C) int x[4] [ ]; D) int x[ ][5]; 10. data type of variable f and i：
float f=3.14; int i;
which expression of following is legal.
A) i=(int)f%5 B) i=int(f)%5 C) i=f%5 D) i=(int f)%5
11. Which one of following marks can be defined as identifier?
A) main B) _0 C)void D) sizeof
12. Having initialization: int a=6,b=5,c=8,d=7,m=2,n=2; the value of m and n after executed the expression (m=c
A) 0 0 B) 0 2 C) 0 1 D) 2 2
13. Having declaration statement:char s[]="\123\\100a\t"; int a=sizeof(s);
The value of a is
A) 7 B)8 C) 13 D) 11 14. while((ch=getchar()) ==’e’) printf(“*”);
Having inputted abcde, The number of * outputted is A) 0 B)1 C)2 D) 3 15. The following is a segment of a program: int a[10]={0,1,2,3,4,5,6,7,8,9},*p=&a[3],b; b=p[5]; The value of b is A) 6 B) 7 C) 8 D) 9
16. According to the declaration: int p[5], *a[5]; the expression ______ is correct.
A) p=a B) p[0]=a C) *(a+1)=p D) a[0]=2
17. Fill in the blank and complete the following function used to calculate the sum of two integers, and return the result by formal parameter. void func(int x,int y, ) { *z=x+y; }
A) int *z B) int z C) &z D)int &z
18. What will be output after execution of following programming?
main()
{ char s[]="136", *p= s; printf("%c",*p++); printf("%c",*++p); }
A) 13 B) 23 C) 16 D) 26 19. What will be output after execution of following programming?
main(){int i,j; char a[ ]=”Excellent!”; a[5]=0;i=sizeof(a); j=strlen(a); printf(“%d,%d\b”,i,j); }
A) 5，11 B) 6，11 C) 10，6 D) 11，5 20. What will be output after execution of following programming?
main()
{ int x=5,a=0,b=0;
switch(x){ case 0:a++; break; case 1:b++; break; case 2:a++; break; } printf(“a=%d,b=%d\n”,a,b); }
A) a=2,b=1 B) a=1,b=1 C) a=1,b=0 D) a=0,b=0 Part Ⅱ
Consider the following programs and write what will be output after execution (There are 10 questions, each of which is worth 5 marks. total 50.)
1
得 分 评阅人
1. main() { int a, b; for(a=1, b=1; a<=100; a++) { if(b>=10) break ; if (b%3==1) { b+=3; continue; } } printf(“%d\n”,a); } 2.
#include "stdio.h" #include "conio.h" main()
{ int digit, sum=0, num=1234; while(num!=0) {
digit=num%10; num=num/10; sum+=digit; }
printf("%d ", sum); } 3. main() { int a=15,b=21,m=0; switch(a%3) { case 0:m++;break; case 1:m++; } switch(b%2) { default:m++; case 0:m++;break;} printf("%d\n",m); }
4.
#define MAX(x,y) (x)>(y)?(x):(y) main()
{ int a=5,b=2, c=3,d=3,t; t=MAX(a+b,c+d) *10; printf(“%d\n”,t); } 5.
#include main()
{ int k=0,*ps, a[11]={ 1,2,3,4,5,6,7,8,9,10}; for(ps=a;*ps!=0; ps+=2) k+=*ps;
printf(“%d\n”,k); } 6.
#include #include main()
{ char *s=“Henan”, *ss=”Hebei”;
strcmp(ss, s)<0? printf(“%s”,ss): printf(“%s”,s);} 7.
#include
void move(char *str, int n) { char temp ; int i;
temp=str[0];
for(i= 1; i str[i-1]=str[i]; str[n-1]=temp;
} main()
{ char s[]=”abcdef”;
int i, z; int n=3; z=strlen(s);
for(i=1; i<=n; i++) move(s,z); printf("%s\n",s);
}
2
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